# Mandelbrot in Python

I just found a nice Python script that draws the Mandelbrot set.

```
_ = (
255,
lambda
V ,B,c
:c and Y(V*V+B,B, c
-1)if(abs(V)<6)else
( 2+c-4*abs(V)**-0.4)/i
) ;v, x=1500,1000;C=range(v*x
);import struct;P=struct.pack;M,\
j ='<QIIHHHH',open('M.bmp','wb').write
for X in j('BM'+P(M,v*x*3+26,26,12,v,x,1,24))or C:
i ,Y=_;j(P('BBB',*(lambda T:(T*80+T**9
*i-950*T **99,T*70-880*T**18+701*
T **9 ,T*i**(1-T**45*2)))(sum(
[ Y(0,(A%3/3.+X%v+(X/v+
A/3/3.-x/2)/1j)*2.5
/x -2.7,i)**2 for \
A in C
[:9]])
/9)
) )
```

You can change the output dimension in line 8. Just make sure that the width is dividable by 4.

I ran the script with a resolution of 3000x2000 px on my T400 with an Intel Core2Duo P8600 @ 2.40GHz and 4GB RAM. I used Python 2.7.2-2 on Arch Linux 64bit and it took took me half an our. And as stated in the article as well, PyPy 1.6-2 should be much faster. And I can confirm that. It only runs half the time of the regular Python implementation:

```
$ time python2 mandelbrot.py
real 29m16.779s
user 29m12.519s
sys 0m0.977s
$ time pypy mandelbrot.py
real 16m21.750s
user 16m18.200s
sys 0m1.320s
```

And here the download link. I converted the file M.bmp, which had a size of 18MB to PNG with a size of 1.7MB: